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learn:fundamentals:circuits:current:start [2016/07/22 21:38] – [Answers] Marthalearn:fundamentals:circuits:current:start [2022/10/04 11:38] (current) – external edit 127.0.0.1
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 ==== Answers ==== ==== Answers ====
 1.  1. 
-a. I = 3A. (The current leaving node b must equal the current entering node a.) +  * a.) I = 3A. (The current leaving node b must equal the current entering node a.) 
-b. I = -2A. (The current entering node b is 2A. Therefore, we must have 2A //leaving// node a. However, the sign convention associated with $I$ is that positive current is //entering// node a, so the current $I$ must be a //negative// 2A) +  * b.) I = -2A. (The current entering node b is 2A. Therefore, we must have 2A //leaving// node a. However, the sign convention associated with $I$ is that positive current is //entering// node a, so the current $I$ must be a //negative// 2A) 
-c. I = -3A. (The current leaving node b is equal to the current entering node a.)+  * c.) I = -3A. (The current leaving node b is equal to the current entering node a.)
  
 2.  2. 
-a. 3A is entering node a. +  * a.) 3A is entering node a. 
-b. 2A is entering node b. (Since 2A is leaving node a.) +  * b.) 2A is entering node b. (Since 2A is leaving node a.) 
-c. 4A is entering node b. (Since //negative// 4A is //leaving// node b.)+  * c.) 4A is entering node b. (Since //negative// 4A is //leaving// node b.)
  
 {{tag>learn fundamentals circuits current}} {{tag>learn fundamentals circuits current}}