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learn:courses:real-analog-chapter-8:start [2017/01/10 21:03] – Marthalearn:courses:real-analog-chapter-8:start [2022/10/04 11:38] (current) – external edit 127.0.0.1
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 ====== Real Analog: Chapter 8 ====== ====== Real Analog: Chapter 8 ======
 +[[{}/learn/courses/real-analog-chapter-7/start|Back to Chapter 7]]
 +-->Chapter 8 Materials#  
 +  * Lecture Material:
 +    * {{ :learn:courses:real-analog-chapter-8:lecture20_b_.ppt |Lecture 20(b) PowerPoint Slides}}: First-order circuit step response, introduction to second-order systems
 +    * {{ :learn:courses:real-analog-chapter-8:lecture21.ppt |Lecture 21 PowerPoint Slides}}: Second-order circuit natural response, sinusoidal signals & complex exponentials
 +    * {{ :learn:courses:real-analog-chapter-8:lecture22.ppt |Lecture 22 PowerPoint Slides}}: Second-order system natural response, mathematical form of solutions, qualitative interpretation
 +    * {{ :learn:courses:real-analog-chapter-8:lecture23.ppt |Lecture 23 PowerPoint Slides}}: Second-order system step response, governing equation, mathematical expression, estimating step response, examples
 +    * [[http://www.youtube.com/watch?v=iDZOK86gjMI&list=PLDEC730F6A8CDE318&index=23&feature=plpp_video| Lecture 20(b) Video]]
 +    * [[http://www.youtube.com/watch?v=lOaav2j-ZjM&list=PLDEC730F6A8CDE318&index=24&feature=plpp_video| Lecture 21 Video]]
 +    * [[http://www.youtube.com/watch?v=lcjf9lQXjSw&list=PLDEC730F6A8CDE318&index=25&feature=plpp_video| Lecture 22 Video]]
 +    * [[http://www.youtube.com/watch?v=uUP4J7dyF8o&list=PLDEC730F6A8CDE318&index=26&feature=plpp_video| Lecture 23 Video]]
 +  * Chapter 8 Video:
 +    * [[http://www.youtube.com/watch?v=TIeKihNmNZM&list=PL170A01159D42313D&index=18&feature=plpp_video| Lab 8 Video 1]]: Second Order Circuit Step Response: Measuring the step response of a series RLC circuit. The measured peak value of the response is compared to analytical expectations.
 +  * {{ :learn:courses:real-analog-chapter-8:real-analog-chapter-8.pdf | Chapter 8 Complete PDF}}
 +    * {{ :learn:courses:real-analog-chapter-8:lab8p5p1.pdf |Lab 8.5.1}}
 +      * {{ :learn:courses:real-analog-chapter-8:lab8p5p1_worksheet.docx |Worksheet 8.5.1}}
 +    * {{ :learn:courses:real-analog-chapter-8:lab8p5p2.pdf |Lab 8.5.2}}
 +      * {{ :learn:courses:real-analog-chapter-8:lab8p5p2_worksheet.docx |Worksheet 8.5.2}}
 +    * {{ :learn:courses:real-analog-chapter-8:lab8p5p3.pdf |Lab 8.5.3}}
 +      * {{ :learn:courses:real-analog-chapter-8:lab8p5p3_worksheet.docx |Worksheet 8.5.3}}
 +  * {{ :learn:courses:real-analog-chapter-8:realanalog-exercisesolutions-chapter8.pdf |Exercise Solutions}}: Chapter 8 exercise solutions
 +  * {{ :learn:courses:real-analog-chapter-8:homework8.docx |Homework}}: Chapter 8 homework problems
 +
 +<--
 +
 ====== 8. Introduction and Chapter Objectives ====== ====== 8. Introduction and Chapter Objectives ======
-Second order systems are, by definition, systems whose input-output relationship is a //second order// differential equation. A second order differential equation contains a //second order derivative// but no derivative higher than second order. Second order systems contain //two independent energy storage elements//, per our comments in [[https://reference.digilentinc.com/learn/courses/real-analog-chapter-7/start|Chapter 7]] pertaining to the relationship between the number of energy storage elements in a system and the system order+Second order systems are, by definition, systems whose input-output relationship is a //second order// differential equation. A second order differential equation contains a //second order derivative// but no derivative higher than second order. Second order systems contain //two independent energy storage elements//, per our comments in [[/learn/courses/real-analog-chapter-7/start|Chapter 7]] pertaining to the relationship between the number of energy storage elements in a system and the system order
  
 Second order systems, like first order systems, are an extremely important class of systems. In previous chapters, we saw that the natural response of first order systems decays exponentially with time – the natural response decays monotonically to zero. The natural response of second order systems can, however, oscillate with time – we will see that a second order systems response can contain sinusoidal components. The motion of a pendulum, for example, can be modeled by a second order system. These oscillations are due to the transfer of energy between the two energy storage mechanisms; a pendulum, for example, oscillates because of the cyclic exchange of potential and kinetic energy of the mass. Second order systems, like first order systems, are an extremely important class of systems. In previous chapters, we saw that the natural response of first order systems decays exponentially with time – the natural response decays monotonically to zero. The natural response of second order systems can, however, oscillate with time – we will see that a second order systems response can contain sinusoidal components. The motion of a pendulum, for example, can be modeled by a second order system. These oscillations are due to the transfer of energy between the two energy storage mechanisms; a pendulum, for example, oscillates because of the cyclic exchange of potential and kinetic energy of the mass.
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 Where $K_1$ and $K_2$ are constants which depend upon the system initial conditions. Where $K_1$ and $K_2$ are constants which depend upon the system initial conditions.
  
-  * The form of the $e^{\pm \omega_n \sqrt{\zeta^2-1})t}$ terms in the system response depends strongly upon the damping ratio. If $\zeta > 1$, these terms become growing or decaying exponentials. If $\zeta<1$, these terms are complex exponentials, and the solution will have sinusoidal components. The relationship between complex exponentials is presented in more depth in section 8.3. If $\zeta=1$, the $e^{\pm \omega_n \sqrt{\zeta^2-1})t}$ are simply one. +  * The form of the $e^{\pm (\omega_n \sqrt{\zeta^2-1})t}$ terms in the system response depends strongly upon the damping ratio. If $\zeta > 1$, these terms become growing or decaying exponentials. If $\zeta<1$, these terms are complex exponentials, and the solution will have sinusoidal components. The relationship between complex exponentials is presented in more depth in section 8.3. If $\zeta=1$, the $e^{\pm (\omega_n \sqrt{\zeta^2-1})t}$ are simply one. 
   * The $e^{-\zeta \omega_nt}$ term in the natural response causes the overall solution to decay as time increases. Thus, the natural response goes to zero as $t \rightarrow \infty$.   * The $e^{-\zeta \omega_nt}$ term in the natural response causes the overall solution to decay as time increases. Thus, the natural response goes to zero as $t \rightarrow \infty$.
  
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 $$\omega = \frac{2\pi}{T}     (Eq. 8.20)$$ $$\omega = \frac{2\pi}{T}     (Eq. 8.20)$$
 +
 +{{ :learn:courses:real-analog-chapter-8:fig_8-5.png?nolink&400 |}}
 +
 +
  
 === Note: === === Note: ===
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 $$A=|A| e^{j \theta_A}     (Eq. 8.32)$$ $$A=|A| e^{j \theta_A}     (Eq. 8.32)$$
  
-We can generalize our definition of the complex exponential to time-varying signals. If we define a time varying signal $e^{j \omega t}$$ , we can use equation (8.31) to write:+We can generalize our definition of the complex exponential to time-varying signals. If we define a time varying signal $e^{j \omega t}$ , we can use equation (8.31) to write:
  
 $$e^{\pm j \omega t} = \cos \omega t \pm j \sin \omega t       (Eq. 8.33)$$ $$e^{\pm j \omega t} = \cos \omega t \pm j \sin \omega t       (Eq. 8.33)$$
  
-The signal $e^{j \omega t}$ can be visualized as a unit vector rotating around the origin in the complex plane; the tip of the vector scribes a unit circle with its center at the origin of the complex plane. This is illustrated in Figure 8.7. The vector rotates at a rate defined by the quantity $\omega$ -- the vector makes one complete revolution every $\frac{2\pi}{\omega} seconds. +The signal $e^{j \omega t}$ can be visualized as a unit vector rotating around the origin in the complex plane; the tip of the vector scribes a unit circle with its center at the origin of the complex plane. This is illustrated in Figure 8.7. The vector rotates at a rate defined by the quantity $\omega$ -- the vector makes one complete revolution every $\frac{2\pi}{\omega}$ seconds. 
  
 The projection of this rotating vector on the real axis traces out the signal $\cos \omega t$ , as shown in Figure 8.7, while the projection of the rotating vector on the imaginary axis traces out the signal $\sin \omega t$, also shown in Figure 8.7. The projection of this rotating vector on the real axis traces out the signal $\cos \omega t$ , as shown in Figure 8.7, while the projection of the rotating vector on the imaginary axis traces out the signal $\sin \omega t$, also shown in Figure 8.7.
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 In equation (8.37), the $e^{-\zeta \omega_n t}$ term is a decaying exponential with time constant $\frac{1}{\zeta \omega_n}$. The $e^{\omega_n t \sqrt{\zeta^2-1}}$ is a growing exponential with time constant $\frac{1}{\omega_n \sqrt{\zeta^2-1}}$. Thus, the overall system response is a sum of two decaying exponential signals, one which is proportional to $e^{-\zeta \omega_n t} \cdot e^{\omega_n t \sqrt{\zeta^2-1}}$ and the other which is proportional to $e^{-\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$.  In equation (8.37), the $e^{-\zeta \omega_n t}$ term is a decaying exponential with time constant $\frac{1}{\zeta \omega_n}$. The $e^{\omega_n t \sqrt{\zeta^2-1}}$ is a growing exponential with time constant $\frac{1}{\omega_n \sqrt{\zeta^2-1}}$. Thus, the overall system response is a sum of two decaying exponential signals, one which is proportional to $e^{-\zeta \omega_n t} \cdot e^{\omega_n t \sqrt{\zeta^2-1}}$ and the other which is proportional to $e^{-\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$. 
  
-The term $e^{-\zeta \omega_n t} \cdot e^{\omega_n t \sqrt{\zeta^2-1}}$ is the product of two exponentials: one which grows with time, and the other which decays with time. The decaying exponential time constant, $\frac{1}{\zeta \omega_n}$, is smaller than the growing exponential time constant, $\frac{1}{\omega_n \sqrt{\zeta^2-1}}$. Thus, the product of the two will decay with time, though the decay rate may be very slow. (Note that in the limit as $\zeta \rightarrow$, $\frac{1}{\zeta \omega_n} \approx \frac{1}{\omega_n \sqrt{\zeta^2-1}}$, the two time constants are nearly identical, and this term becomes constant with time.)+The term $e^{-\zeta \omega_n t} \cdot e^{\omega_n t \sqrt{\zeta^2-1}}$ is the product of two exponentials: one which grows with time, and the other which decays with time. The decaying exponential time constant, $\frac{1}{\zeta \omega_n}$, is smaller than the growing exponential time constant, $\frac{1}{\omega_n \sqrt{\zeta^2-1}}$. Thus, the product of the two will decay with time, though the decay rate may be very slow. (Note that in the limit as $\zeta \rightarrow \infty$, $\frac{1}{\zeta \omega_n} \approx \frac{1}{\omega_n \sqrt{\zeta^2-1}}$, the two time constants are nearly identical, and this term becomes constant with time.) 
  
-The term $e^{-\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$ is the product of two exponentials: one which grows with time, and the other which decays with time. The decaying exponential time constant, $\frac{1}{\zeta \omega_n}$, is smaller than the growing exponential time constant, $\frac{1}{\omega_n \sqrt{\zeta^2-1}}$. Thus, the product of the two will decay with time, though the decay rate may be very slow. (Note that in the limit as $\zeta \rightarrow$, $\frac{1}{\zeta \omega_n} \approx \frac{1}{\omega_n \sqrt{\zeta^201}}$, the two time constants are nearly identical, and this term becomes constant with time.) 
  
 The term $e^{\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$ is the product of two decaying exponentials; this term will, in general, decay quickly relative to the $e^{\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$ term. The term $e^{\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$ is the product of two decaying exponentials; this term will, in general, decay quickly relative to the $e^{\zeta \omega_n t} \cdot e^{-\omega_n t \sqrt{\zeta^2-1}}$ term.
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 For an underdamped system, $\zeta <1$, and equation (8.36) becomes as shown in equation (8.38).  For an underdamped system, $\zeta <1$, and equation (8.36) becomes as shown in equation (8.38). 
  
-$$y_h(t)=e^{-\zeta \omega_n t} \left[ \frac{\dot{y}_0 + \zeta \omega_n y_0}{\omega_n \sqrt{1-\zeta^2}} \sin \left( \omega_n t \sqrt{1-\zeta^2} \right) + y_0 \cos \left( \omega_n t \sqrt{1-zeta^2} \right) \right]  (Eq. 8.38)$$+$$y_h(t)=e^{-\zeta \omega_n t} \left[ \frac{\dot{y}_0 + \zeta \omega_n y_0}{\omega_n \sqrt{1-\zeta^2}} \sin \left( \omega_n t \sqrt{1-\zeta^2} \right) + y_0 \cos \left( \omega_n t \sqrt{1-\zeta^2} \right) \right]  (Eq. 8.38)$$
  
 The solution is a decaying sinusoid. The decay rate is set by the term $e^{-\zeta \omega_n t}$, while the oscillation frequency of the sinusoid is $\omega_n \sqrt{1-\zeta^2}$. The oscillation frequency seen in the natural response is thus not identically the natural frequency of the system; it is also influenced by the damping ratio. This leads to the definition of the //damped natural frequency//: The solution is a decaying sinusoid. The decay rate is set by the term $e^{-\zeta \omega_n t}$, while the oscillation frequency of the sinusoid is $\omega_n \sqrt{1-\zeta^2}$. The oscillation frequency seen in the natural response is thus not identically the natural frequency of the system; it is also influenced by the damping ratio. This leads to the definition of the //damped natural frequency//:
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 **d.)** In order for the system to be critically damped, the damping ratio $\zeta = 1$. From equation (8.47) with $\zeta = 1$, we obtain:  **d.)** In order for the system to be critically damped, the damping ratio $\zeta = 1$. From equation (8.47) with $\zeta = 1$, we obtain: 
  
-$$2 \zeta \omega_n = \frac{1R}{L} \Rightarrow 2(1)(1000) = \frac{2R}{1H} \Rightarrow = 1000 \Omega$$+$$2 \zeta \omega_n = \frac{1R}{L} \Rightarrow 2(1)(1000) = \frac{2R}{1H} \Rightarrow R = 1000 \Omega$$
  
 **e.)** Initial conditions on $v_C(t)$ are $v_C(0)$ and $\frac{dv_C(t)}{dt} |_{t=0}$ We are given $v_C(-)=1V$ in the problem statement, but we need to determine $\frac{dv_C(t)}{dt} |_{t=0}$; the current through the inductor, $i_L(0)$ can be used to determine this. The current through the inductor is related to the capacitor voltage via equation (8.43) above: **e.)** Initial conditions on $v_C(t)$ are $v_C(0)$ and $\frac{dv_C(t)}{dt} |_{t=0}$ We are given $v_C(-)=1V$ in the problem statement, but we need to determine $\frac{dv_C(t)}{dt} |_{t=0}$; the current through the inductor, $i_L(0)$ can be used to determine this. The current through the inductor is related to the capacitor voltage via equation (8.43) above:
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 $$y(t)=y_h(t) + y_p(t)$$ $$y(t)=y_h(t) + y_p(t)$$
  
-The homogeneous solution of second order differential equations has been discussed in sections 8.1 and 8.4 and will not be repeated here. The particular solution of the differential equation (8.51) can be obtained by examining the solution to the equation after the homogeneous solution has died out. Letting $t \rightarrow \infty$ in equation (8.51) and noting that the forcing function is a constant as $t \rightarrow \infty$ allows us to set $\frac{d^2y(t \rightarrow \infty}{dt^2} = \frac{dy(t \rightarrow \infty)}{dt} = 0$ amd thus, +The homogeneous solution of second order differential equations has been discussed in sections 8.1 and 8.4 and will not be repeated here. The particular solution of the differential equation (8.51) can be obtained by examining the solution to the equation after the homogeneous solution has died out. Letting $t \rightarrow \infty$ in equation (8.51) and noting that the forcing function is a constant as $t \rightarrow \infty$ allows us to set $\frac{d^2y(t \rightarrow \infty)}{dt^2} = \frac{dy(t \rightarrow \infty)}{dt} = 0$ and thus, 
  
 $$\omega_{n}^{2} y_P(t) = A \Rightarrow y_P(t) = \frac{A}{\omega_{n}^{2}}       (Eq. 8.53)$$ $$\omega_{n}^{2} y_P(t) = A \Rightarrow y_P(t) = \frac{A}{\omega_{n}^{2}}       (Eq. 8.53)$$
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 Combining the particular and homogeneous solutions, assuming the system is underdamped $(\zeta < 1)$, and employing the initial conditions results in our final expression for the __step response of an underdamped second order system__: Combining the particular and homogeneous solutions, assuming the system is underdamped $(\zeta < 1)$, and employing the initial conditions results in our final expression for the __step response of an underdamped second order system__:
  
-$$y(t) = \frac{A}{\omega_{n}^{2}} \left{ 1-e^{- \zeta \omega_n t} \left \cos (\omega_d t) + \frac{\zeta}{\sqrt{1-\zeta^2}} \sin (\omega_d t) \right] \right}    (Eq. 8.54)$$+$$y(t) = \frac{A}{\omega_{n}^{2}} \{ 1-e^{- \zeta \omega_n t} [ \cos (\omega_d t) + \frac{\zeta}{\sqrt{1-\zeta^2}} \sin (\omega_d t) ] \}    (Eq. 8.54)$$
  
 Where $\omega_d = \omega_n \sqrt{1-\zeta^2}$ is the damped natural frequency of the system, previously defined in chapter 8.4. Where $\omega_d = \omega_n \sqrt{1-\zeta^2}$ is the damped natural frequency of the system, previously defined in chapter 8.4.
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 The time domain parameters $M_P$, $t_r$, and $T$ are readily related to the parameters $\xi$, $\omega_n$, and $\omega_d$. We provide the following relations here, without proof: The time domain parameters $M_P$, $t_r$, and $T$ are readily related to the parameters $\xi$, $\omega_n$, and $\omega_d$. We provide the following relations here, without proof:
  
-$$M_P = e^{\frac{-\pi \xi}{\sqrt{1-\xi^2}}   (Eq. 8.56)$$+$$M_P = e^{\frac{-\pi \xi}{\sqrt{1-\xi^2}}}   (Eq. 8.56)$$
  
 $$t_r \approx \frac{1.8}{\omega_n}    (Eq. 8.57)$$ $$t_r \approx \frac{1.8}{\omega_n}    (Eq. 8.57)$$
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   * The rise time and maximum overshoot can be related to the damping ratio and natural frequency of the system. The appropriate relations are provided below:   * The rise time and maximum overshoot can be related to the damping ratio and natural frequency of the system. The appropriate relations are provided below:
       * $t_r \approx \frac{1.8}{\omega_n}$       * $t_r \approx \frac{1.8}{\omega_n}$
-      * $M_P=e^{frac{-\pi \xi}{\sqrt{1-\xi^2}}$ or $M_P - \frac{\xi}{0.6}$ (for small damping ratios, $\xi < 0.6$)+      * $M_P=e^{\frac{- \pi \xi}{\sqrt{1-\xi^2}}}$ or $M_P - \frac{\xi}{0.6}$ (for small damping ratios, $\xi < 0.6$)
  
 The period of the oscillations can be used to cross-check the above results, since it depends upon both the damping ratio and natural frequency. The period of the oscillations can be used to cross-check the above results, since it depends upon both the damping ratio and natural frequency.
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 {{ :learn:courses:real-analog-chapter-8:chapter8s.png |Example image 1.}} {{ :learn:courses:real-analog-chapter-8:chapter8s.png |Example image 1.}}
 +
 +[[{}/learn/courses/real-analog-chapter-7/start|Back to Chapter 7]]
 +[[{}/learn/courses/real-analog-chapter-9/start|Go to Chapter 9]]