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| daq-and-datalogging:documents:linear_transducer_scaling [2023/07/17 05:07] – created Scandiweb | daq-and-datalogging:documents:linear_transducer_scaling [2023/07/17 05:08] (current) – Scandiweb | ||
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| To begin, I am using a device that has differential inputs, which means that each input has two connections – one (+) and one (-). In order to convert current to a voltage a resistor is installed into the loop completing the current loop of the sensor – refer to the configuration below for signal hookup.\\ | To begin, I am using a device that has differential inputs, which means that each input has two connections – one (+) and one (-). In order to convert current to a voltage a resistor is installed into the loop completing the current loop of the sensor – refer to the configuration below for signal hookup.\\ | ||
| + | <WRAP centeralign> | ||
| {{https:// | {{https:// | ||
| + | </ | ||
| Doing the math (Ohm’s Law) the resistor will produce values between 1 and 5 volts. Knowing this I setup my two equations as follows\\ | Doing the math (Ohm’s Law) the resistor will produce values between 1 and 5 volts. Knowing this I setup my two equations as follows\\ | ||
| Line 19: | Line 21: | ||
| 3000 = 5X + B and\\ | 3000 = 5X + B and\\ | ||
| - | 0 = 1X + B\\ | + | 0 = 1X + B\\ |
| - | + | ||
| - | + | ||
| Using substitution, | Using substitution, | ||